The figure shows a velocity-time graph of a p | vedclass

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Question

Distance $=$ Area convered by $v-t$ graph on time axis $\Rightarrow \frac{1}{2}\left(+\frac{14}{3}ight) 	imes 10+\frac{1}{2} 	imes\left(8-\frac{14

Vedclass · Accepted Answer

$66.6$

Vedclass · Answer

Distance $=$ Area convered by $v-t$ graph on time axis $\Rightarrow \frac{1}{2}\left(+\frac{14}{3}ight) 	imes 10+\frac{1}{2} 	imes\left(8-\frac{14}{3}ight) 	imes 20$

$=\frac{100}{3}+\frac{100}{3}=\frac{200}{3} \Rightarrow 66.6 \mathrm{m}$

The figure shows a velocity-time graph of a particle moving along a straight line The total distance travelled by the particle is ........ $m$

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