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2.Motion in Straight Line
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The figure shows a velocity-time graph of a particle moving along a straight line The total distance travelled by the particle is ........ $m$
A$66.6$
B$51.6 $
C$0$
D$36.6$
Solution
Distance $=$ Area convered by $v-t$ graph on time axis $\Rightarrow \frac{1}{2}\left(+\frac{14}{3}\right) \times 10+\frac{1}{2} \times\left(8-\frac{14}{3}\right) \times 20$
$=\frac{100}{3}+\frac{100}{3}=\frac{200}{3} \Rightarrow 66.6 \mathrm{m}$
$=\frac{100}{3}+\frac{100}{3}=\frac{200}{3} \Rightarrow 66.6 \mathrm{m}$
Standard 11
Physics
